The purpose of this vignette is to learn how to estimate trophic position of a species using stable isotope data (δ13C and δ15N). We can estimate trophic position using a one source model based on equations from Post 2002.
The equation for a one source model consists of the following:
$$ \text{Trophic Position} = \lambda + \frac{(\delta^{15}N_c - \delta^{15}N_b)}{\Delta N} $$
Where λ is the trophic
position of the baseline (e.g., 2
), δ15Nc
is the δ15N of the
consumer, δ15Nb
is the mean δ15N of the
baseline, and ΔN is
the trophic enrichment factor (e.g., 3.4).
To use this model with a Bayesian framework, we need to rearrange this equation to the following:
δ15Nc = δ15Nb + ΔN × (Trophic Position − λ)
The function one_source_model()
uses this rearranged
equation.
First we need to organize the data prior to running the model. To do this work we will use {dplyr} and {tidyr} but we could also use {data.table}.
When running the model we will use {trps} and {brms} and iterative processes provided by {purrr}.
Once we have run the model we will use {bayesplot} to assess models and then extract posterior draws using {tidybayes}. Posterior distributions will be plotted using {ggplot2} and {ggdist} with colours provided by {viridis}.
First we load all the packages needed to carry out the analysis.
In {trps} we have several data sets, they include stable isotope data (δ13C and δ15N) for a consumer, lake trout (Salvelinus namaycush), a benthic baseline, amphipods, and a pelagic baseline, dreissenids, for an ecoregion in Lake Ontario.
We check out each data set with the first being the consumer.
consumer_iso
#> # A tibble: 30 × 4
#> common_name ecoregion d13c d15n
#> <fct> <fct> <dbl> <dbl>
#> 1 Lake Trout Embayment -22.9 15.9
#> 2 Lake Trout Embayment -22.5 16.2
#> 3 Lake Trout Embayment -22.8 17.0
#> 4 Lake Trout Embayment -22.3 16.6
#> 5 Lake Trout Embayment -22.5 16.6
#> 6 Lake Trout Embayment -22.3 16.6
#> 7 Lake Trout Embayment -22.3 16.6
#> 8 Lake Trout Embayment -22.5 16.2
#> 9 Lake Trout Embayment -22.9 16.4
#> 10 Lake Trout Embayment -22.3 16.3
#> # ℹ 20 more rows
We can see that this data set contains the common_name
of the consumer , the ecoregion
samples were collected
from, and δ13C
(d13c
) and δ15N
(d15n
).
Next we check out the benthic baseline data set.
baseline_1_iso
#> # A tibble: 14 × 5
#> common_name ecoregion d13c_b1 d15n_b1 id
#> <fct> <fct> <dbl> <dbl> <int>
#> 1 Amphipoda Embayment -26.2 8.44 1
#> 2 Amphipoda Embayment -26.6 8.77 2
#> 3 Amphipoda Embayment -26.0 8.05 3
#> 4 Amphipoda Embayment -22.1 13.6 4
#> 5 Amphipoda Embayment -24.3 6.99 5
#> 6 Amphipoda Embayment -22.1 7.95 6
#> 7 Amphipoda Embayment -24.7 7.37 7
#> 8 Amphipoda Embayment -26.6 6.93 8
#> 9 Amphipoda Embayment -24.6 6.97 9
#> 10 Amphipoda Embayment -22.1 7.95 10
#> 11 Amphipoda Embayment -24.7 7.37 11
#> 12 Amphipoda Embayment -22.1 7.95 12
#> 13 Amphipoda Embayment -24.7 7.37 13
#> 14 Amphipoda Embayment -26.9 10.2 14
We can see that this data set contains the common_name
of the baseline, the ecoregion
samples were collected from,
and δ13C
(d13c_b1
) and δ15N
(d15n_b1
).
Now that we understand the data we need to combine both data sets to estimate trophic position for our consumer.
To do this we first need to make an id
column in each
data set, which will allow us to join them together. We first
arrange()
the data by ecoregion
and
common_name
. Next we group_by()
the same
variables, and add id
for each grouping using
row_number()
. Always ungroup()
the
data.frame
after using group_by()
. Lastly, we
use dplyr::select()
to rearrange the order of the
columns.
Let’s first add id
to consumer_iso
data
frame.
Next let’s add id
to baseline_1_iso
data
frame. For joining purposes we are going to drop
common_name
from this data frame.
Now that we have the consumer and baseline data sets in a consistent
format we can join them by "id"
and
"ecoregion"
using left_join()
from {dplyr}.
We can see that we have successfully combined our consumer and
baseline data. We need to do one last thing prior to analyzing the data,
and that is calculate the mean δ13C
(c1
) and δ15N
(n1
) for the baseline and add in the constant λ (l1
) to our data
frame. We do this by using groub_by()
to group the data by
our two groups, then using mutate()
and mean()
to calculate the mean values.
Important note, to run the model successfully, columns need to be
named d15n
, n1
, and l1
.
combined_iso_os <- combined_iso_os %>%
group_by(ecoregion, common_name) %>%
mutate(
c1 = mean(d13c_b1, na.rm = TRUE),
n1 = mean(d15n_b1, na.rm = TRUE),
l1 = 2
) %>%
ungroup()
Let’s view our combined data.
combined_iso_os
#> # A tibble: 30 × 10
#> id common_name ecoregion d13c d15n d13c_b1 d15n_b1 c1 n1 l1
#> <int> <fct> <fct> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl>
#> 1 1 Lake Trout Embayment -22.9 15.9 -26.2 8.44 -24.6 8.28 2
#> 2 2 Lake Trout Embayment -22.5 16.2 -26.6 8.77 -24.6 8.28 2
#> 3 3 Lake Trout Embayment -22.8 17.0 -26.0 8.05 -24.6 8.28 2
#> 4 4 Lake Trout Embayment -22.3 16.6 -22.1 13.6 -24.6 8.28 2
#> 5 5 Lake Trout Embayment -22.5 16.6 -24.3 6.99 -24.6 8.28 2
#> 6 6 Lake Trout Embayment -22.3 16.6 -22.1 7.95 -24.6 8.28 2
#> 7 7 Lake Trout Embayment -22.3 16.6 -24.7 7.37 -24.6 8.28 2
#> 8 8 Lake Trout Embayment -22.5 16.2 -26.6 6.93 -24.6 8.28 2
#> 9 9 Lake Trout Embayment -22.9 16.4 -24.6 6.97 -24.6 8.28 2
#> 10 10 Lake Trout Embayment -22.3 16.3 -22.1 7.95 -24.6 8.28 2
#> # ℹ 20 more rows
It is now ready to be analyzed!
We can now estimate trophic position for lake trout in an ecoregion of Lake Ontario.
There are a few things to know about running a Bayesian analysis, I suggest reading these resources:
Bayesian analyses rely on supplying uninformed or informed prior
distributions for each parameter (coefficient; predictor) in the model.
The default informed priors for a one source model are the following,
ΔN assumes a normal
distribution (dn
; μ = 3.4; σ = 0.25), trophic position assumes
a uniform distribution (lower bound = 2 and upper bound = 10), σ assumes a uniform distribution
(lower bound = 0 and upper bound = 10), and if informed priors are
desired for δ15Nb
(n1
; μ = 9; σ = 1), we can set the argument
bp
to TRUE
in all one_source_
functions.
You can change these default priors using
one_source_priors_params()
, however, I would suggest
becoming familiar with Bayesian analyses, your study species, and system
prior to adjusting these values.
It is important to always run the model with at least 2 chains. If the model does not converge you can try to increase the following:
The amount of samples that are burned-in (discarded; in
brm()
this can be controlled by the argument
warmup
)
The number of iterative samples retained (in brm()
this can be controlled by the argument iter
).
The number of samples drawn (in brm()
this is
controlled by the argument thin
).
The adapt_delta
value using
control = list(adapt_delta = 0.95)
.
When assessing the model we want R̂ to be 1 or within 0.05 of 1, which indicates that the variance among and within chains are equal (see {rstan} documentation on R̂), a high value for effective sample size (ESS), trace plots to look “grassy” or “caterpillar like,” and posterior distributions to look relatively normal.
We will use functions from {trps} that drop into a
{brms} model. These
functions are one_source_model()
which provides
brm()
the formula structure needed to run a one source
model. Next brm()
needs the structure of the priors which
is supplied to the prior
argument using
one_source_priors()
. Lastly, values for these priors are
supplied through the stanvars
argument using
one_source_priors_params()
. You can adjust the mean (μ), variance (σ), or upper and lower bounds
(lb
and ub
) for each prior of the model using
one_source_priors_params()
, however, only adjust priors if
you have a good grasp of Bayesian frameworks and your study system and
species.
Let’s run the model!
Let’s view the summary of the model.
m
#> Family: gaussian
#> Links: mu = identity; sigma = identity
#> Formula: d15n ~ n1 + dn * (tp - l1)
#> dn ~ 1
#> tp ~ 1
#> Data: combined_iso_os (Number of observations: 30)
#> Draws: 2 chains, each with iter = 4000; warmup = 1000; thin = 1;
#> total post-warmup draws = 6000
#>
#> Regression Coefficients:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> dn_Intercept 3.37 0.25 2.89 3.86 1.00 1506 1878
#> tp_Intercept 4.54 0.20 4.21 4.96 1.00 1531 1891
#>
#> Further Distributional Parameters:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> sigma 0.61 0.09 0.47 0.81 1.00 2145 1903
#>
#> Draws were sampled using sampling(NUTS). For each parameter, Bulk_ESS
#> and Tail_ESS are effective sample size measures, and Rhat is the potential
#> scale reduction factor on split chains (at convergence, Rhat = 1).
We can see that R̂ is 1 meaning that variance among and within chains are equal (see {rstan} documentation on R̂) and that ESS is quite large. Overall, this means the model is converging and fitting accordingly.
We can check how well the model is predicting the δ15N of the
consumer using pp_check()
from
{bayesplot}
.
We can see that posteriors draws (yrep; light lines) are effectively modeling δ15N of the consumer ( y; dark line).
Let’s again look at the summary output from the model.
m
#> Family: gaussian
#> Links: mu = identity; sigma = identity
#> Formula: d15n ~ n1 + dn * (tp - l1)
#> dn ~ 1
#> tp ~ 1
#> Data: combined_iso_os (Number of observations: 30)
#> Draws: 2 chains, each with iter = 4000; warmup = 1000; thin = 1;
#> total post-warmup draws = 6000
#>
#> Regression Coefficients:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> dn_Intercept 3.37 0.25 2.89 3.86 1.00 1506 1878
#> tp_Intercept 4.54 0.20 4.21 4.96 1.00 1531 1891
#>
#> Further Distributional Parameters:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> sigma 0.61 0.09 0.47 0.81 1.00 2145 1903
#>
#> Draws were sampled using sampling(NUTS). For each parameter, Bulk_ESS
#> and Tail_ESS are effective sample size measures, and Rhat is the potential
#> scale reduction factor on split chains (at convergence, Rhat = 1).
We can see that ΔN
is estimated to be 3.37
with l-95% CI
of
2.89
, and u-95% CI
of 3.86
. If we
move down to trophic position (tp
) we see trophic position
is estimated to be 4.54
with l-95% CI
of
4.21
, and u-95% CI
of 4.96
.
We use functions from {tidybayes} to do this
work. First we look at the the names of the variables we want to extract
using get_variables()
.
get_variables(m)
#> [1] "b_dn_Intercept" "b_tp_Intercept" "sigma" "lprior"
#> [5] "lp__" "accept_stat__" "stepsize__" "treedepth__"
#> [9] "n_leapfrog__" "divergent__" "energy__"
You will notice that "b_tp_Intercept"
is the name of the
variable that we are wanting to extract. We extract posterior draws
using gather_draws()
, and rename
"b_tp_Intercept"
to tp
.
post_draws <- m %>%
gather_draws(b_tp_Intercept) %>%
mutate(
ecoregion = "Embayment",
common_name = "Lake Trout",
.variable = "tp"
) %>%
dplyr::select(common_name, ecoregion, .chain:.value)
Let’s view the post_draws
post_draws
#> # A tibble: 6,000 × 7
#> # Groups: .variable [1]
#> common_name ecoregion .chain .iteration .draw .variable .value
#> <chr> <chr> <int> <int> <int> <chr> <dbl>
#> 1 Lake Trout Embayment 1 1 1 tp 4.23
#> 2 Lake Trout Embayment 1 2 2 tp 4.26
#> 3 Lake Trout Embayment 1 3 3 tp 4.39
#> 4 Lake Trout Embayment 1 4 4 tp 4.44
#> 5 Lake Trout Embayment 1 5 5 tp 4.33
#> 6 Lake Trout Embayment 1 6 6 tp 4.74
#> 7 Lake Trout Embayment 1 7 7 tp 5.06
#> 8 Lake Trout Embayment 1 8 8 tp 4.40
#> 9 Lake Trout Embayment 1 9 9 tp 4.42
#> 10 Lake Trout Embayment 1 10 10 tp 4.30
#> # ℹ 5,990 more rows
We can see that this consists of seven variables:
ecoregion
common_name
.chain
.iteration
(number of sample after burn-in).draw
(number of samples from iter
).variable
(this will have different variables depending
on what is supplied to gather_draws()
).value
(estimated value)Considering we are likely using this information for a paper or
presentation, it is nice to be able to report the median and credible
intervals (e.g., equal-tailed intervals; ETI). We can extract and export
these values using spread_draws()
and
median_qi
from {tidybayes}.
We rename b_tp_Intercept
to tp
, add the
grouping columns, round all columns that are numeric to two decimal
points using mutate_if()
, and rearrange the order of the
columns using dplyr::select()
.
medians_ci <- m %>%
spread_draws(b_tp_Intercept) %>%
median_qi() %>%
rename(
tp = b_tp_Intercept
) %>%
mutate(
ecoregion = "Embayment",
common_name = "Lake Trout"
) %>%
mutate_if(is.numeric, round, digits = 2) %>%
dplyr::select(ecoregion, common_name, tp:.interval)
Let’s view the output.
medians_ci
#> # A tibble: 1 × 8
#> ecoregion common_name tp .lower .upper .width .point .interval
#> <chr> <chr> <dbl> <dbl> <dbl> <dbl> <chr> <chr>
#> 1 Embayment Lake Trout 4.53 4.21 4.96 0.95 median qi
I like to use {openxlsx} to
export these values into a table that I can use for presentations and
papers. For the vignette I am not going to demonstrate how to do this
but please check out {openxlsx}
.
Now that we have our posterior draws extracted we can plot them. To analyze a single species or group, I like using density plots.
For this example we first plot the density for posterior draws using
geom_density()
.
ggplot(data = post_draws, aes(x = .value)) +
geom_density() +
theme_bw(base_size = 15) +
theme(
panel.grid = element_blank()
) +
labs(
x = "P(Trophic Position | X)",
y = "Density"
)
Next we plot it as a point interval plot using
stat_pointinterval()
.
ggplot(data = post_draws, aes(y = .value,
x = common_name)) +
stat_pointinterval() +
theme_bw(base_size = 15) +
theme(
panel.grid = element_blank()
) +
labs(
x = "P(Trophic Position | X)",
y = "Density"
)
Congratulations we have estimated the trophic position for Lake Trout!
I’ll demonstrate in another vignette how to run the model with an iterative process to produce estimates of trophic position for more than one group (e.g., comparing trophic position among species or in this case different ecoregions).